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(1/x+2)-3=(13/x+2)
We move all terms to the left:
(1/x+2)-3-((13/x+2))=0
Domain of the equation: x+2)!=0
x∈R
Domain of the equation: x+2))!=0We get rid of parentheses
x∈R
1/x-((13/x+2))+2-3=0
We calculate fractions
x/x^2+(-((13*x)/x^2+2-3=0
We add all the numbers together, and all the variables
x/x^2+(-((+13x)/x^2+2-3=0
We calculate fractions
We do not support expression: x^4
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