3(t-4)=2(t-2)+t

Solution for 3(t-4)=2(t-2)+t equation:

3(t-4)=2(t-2)+t

We move all terms to the left:

3(t-4)-(2(t-2)+t)=0

We multiply parentheses

3t-(2(t-2)+t)-12=0


We calculate terms in parentheses: -(2(t-2)+t), so:

2(t-2)+t

We add all the numbers together, and all the variables

t+2(t-2)

We multiply parentheses

t+2t-4

We add all the numbers together, and all the variables

3t-4

Back to the equation:

-(3t-4)


We get rid of parentheses

3t-3t+4-12=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation