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(1/x+2)+3=10/x+2
We move all terms to the left:
(1/x+2)+3-(10/x+2)=0
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
1/x-10/x+2-2+3=0
We multiply all the terms by the denominator
2*x-2*x+3*x+1-10=0
We add all the numbers together, and all the variables
3x-9=0
We move all terms containing x to the left, all other terms to the right
3x=9
x=9/3
x=3
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