2x+2x+(x+3)+(x+3)=78

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Solution for 2x+2x+(x+3)+(x+3)=78 equation: 



2x+2x+(x+3)+(x+3)=78

We move all terms to the left:

2x+2x+(x+3)+(x+3)-(78)=0

We add all the numbers together, and all the variables

4x+(x+3)+(x+3)-78=0

We get rid of parentheses

4x+x+x+3+3-78=0

We add all the numbers together, and all the variables

6x-72=0

We move all terms containing x to the left, all other terms to the right

6x=72

x=72/6

x=12

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