(1/w-3)-(3/4w-12)=(1/4w-12)

Solution for (1/w-3)-(3/4w-12)=(1/4w-12) equation:

D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((3/4)*w)-3+12 = (1/4)*w-12 // - (1/4)*w-12

1/w-((3/4)*w)-((1/4)*w)-3+12+12 = 0

(-3/4)*w+(-1/4)*w+1/w-3+12+12 = 0

1*w^-1-1*w^1+21*w^0 = 0

(21*w^1-1*w^2+1*w^0)/(w^1) = 0 // * w^2

w^1*(21*w^1-1*w^2+1*w^0) = 0

w^1

21*w-w^2+1 = 0

21*w-w^2+1 = 0

DELTA = 21^2-(-1*1*4)

DELTA = 445

DELTA > 0

w = (445^(1/2)-21)/(-1*2) or w = (-445^(1/2)-21)/(-1*2)

w = (445^(1/2)-21)/(-2) or w = (445^(1/2)+21)/2

w in { (445^(1/2)-21)/(-2), (445^(1/2)+21)/2} 

w in { (445^(1/2)-21)/(-2), (445^(1/2)+21)/2 }