7/3=2/(x-5)

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Solution for 7/3=2/(x-5) equation: 


D( x )

x-5 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x in (-oo:5) U (5:+oo)

7/3 = 2/(x-5) // - 2/(x-5)

7/3-(2/(x-5)) = 0

7/3-2*(x-5)^-1 = 0

7/3-2/(x-5) = 0

(-2*3)/(3*(x-5))+(7*(x-5))/(3*(x-5)) = 0

7*(x-5)-2*3 = 0

7*x-41 = 0

(7*x-41)/(3*(x-5)) = 0

(7*x-41)/(3*(x-5)) = 0 // * 3*(x-5)

7*x-41 = 0

7*x-41 = 0 // + 41

7*x = 41 // : 7

x = 41/7

x = 41/7

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