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(1/9)x+40=x
We move all terms to the left:
(1/9)x+40-(x)=0
Domain of the equation: 9)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/9)x-x+40=0
We add all the numbers together, and all the variables
-1x+(+1/9)x+40=0
We multiply parentheses
x^2-1x+40=0
a = 1; b = -1; c = +40;
Δ = b2-4ac
Δ = -12-4·1·40
Δ = -159
Delta is less than zero, so there is no solution for the equation
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