15(y-4)-2(y-2)=-5(y+6)

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Solution for 15(y-4)-2(y-2)=-5(y+6) equation: 



15(y-4)-2(y-2)=-5(y+6)

We move all terms to the left:

15(y-4)-2(y-2)-(-5(y+6))=0

We multiply parentheses

15y-2y-(-5(y+6))-60+4=0



We calculate terms in parentheses: -(-5(y+6)), so:

-5(y+6)

We multiply parentheses

-5y-30

Back to the equation:

-(-5y-30)



We add all the numbers together, and all the variables

13y-(-5y-30)-56=0

We get rid of parentheses

13y+5y+30-56=0

We add all the numbers together, and all the variables

18y-26=0

We move all terms containing y to the left, all other terms to the right

18y=26

y=26/18

y=1+4/9

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