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(1/9)(x+18)+(1/3)(2x+3)=x+3
We move all terms to the left:
(1/9)(x+18)+(1/3)(2x+3)-(x+3)=0
Domain of the equation: 9)(x+18)!=0
x∈R
Domain of the equation: 3)(2x+3)!=0We add all the numbers together, and all the variables
x∈R
(+1/9)(x+18)+(+1/3)(2x+3)-(x+3)=0
We get rid of parentheses
(+1/9)(x+18)+(+1/3)(2x+3)-x-3=0
We multiply parentheses ..
(+x^2+1/9*18)+(+1/3)(2x+3)-x-3=0
We calculate fractions
There is no solution for this equation
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