22x2=440

Solution for 22x2=440 equation:

22x^2=440

We move all terms to the left:

22x^2-(440)=0

a = 22; b = 0; c = -440;
Δ = b2-4ac
Δ = 02-4·22·(-440)
Δ = 38720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{38720}=\sqrt{7744*5}=\sqrt{7744}*\sqrt{5}=88\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88\sqrt{5}}{2*22}=\frac{0-88\sqrt{5}}{44}
=-\frac{88\sqrt{5}}{44}
=-2\sqrt{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88\sqrt{5}}{2*22}=\frac{0+88\sqrt{5}}{44}
=\frac{88\sqrt{5}}{44}
=2\sqrt{5}
$