(1/9)(x+1)=27(3x-1)

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Solution for (1/9)(x+1)=27(3x-1) equation: 



(1/9)(x+1)=27(3x-1)

We move all terms to the left:

(1/9)(x+1)-(27(3x-1))=0



Domain of the equation: 9)(x+1)!=0

x∈R



We add all the numbers together, and all the variables

(+1/9)(x+1)-(27(3x-1))=0

We multiply parentheses ..

(+x^2+1/9*1)-(27(3x-1))=0

We multiply all the terms by the denominator


(+x^2+1-((27(3x-1)))*9*1)=0



We calculate terms in parentheses: +(+x^2+1-((27(3x-1)))*9*1), so:

+x^2+1-((27(3x-1)))*9*1

determiningTheFunctionDomain
x^2-((27(3x-1)))*9*1+1

Back to the equation:

+(x^2-((27(3x-1)))*9*1+1)





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





We calculate terms in parentheses: +(x^2-((27(3x-1)))*9*1+1), so:

x^2-((27(3x-1)))*9*1+1





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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