3x-7=1/4x+26

Solution for 3x-7=1/4x+26 equation:

3x-7=1/4x+26

We move all terms to the left:

3x-7-(1/4x+26)=0


Domain of the equation: 4x+26)!=0

x∈R


We get rid of parentheses

3x-1/4x-26-7=0

We multiply all the terms by the denominator


3x*4x-26*4x-7*4x-1=0

Wy multiply elements

12x^2-104x-28x-1=0

We add all the numbers together, and all the variables

12x^2-132x-1=0

a = 12; b = -132; c = -1;
Δ = b2-4ac
Δ = -1322-4·12·(-1)
Δ = 17472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17472}=\sqrt{64*273}=\sqrt{64}*\sqrt{273}=8\sqrt{273}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-8\sqrt{273}}{2*12}=\frac{132-8\sqrt{273}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+8\sqrt{273}}{2*12}=\frac{132+8\sqrt{273}}{24}
$