(1/6)-3x-2=36x+1

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Solution for (1/6)-3x-2=36x+1 equation:



(1/6)-3x-2=36x+1
We move all terms to the left:
(1/6)-3x-2-(36x+1)=0
We add all the numbers together, and all the variables
-3x-(36x+1)-2+(+1/6)=0
We get rid of parentheses
-3x-36x-1-2+1/6=0
We multiply all the terms by the denominator
-3x*6-36x*6+1-1*6-2*6=0
We add all the numbers together, and all the variables
-3x*6-36x*6-17=0
Wy multiply elements
-18x-216x-17=0
We add all the numbers together, and all the variables
-234x-17=0
We move all terms containing x to the left, all other terms to the right
-234x=17
x=17/-234
x=-17/234

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