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4p^2+8p-45=0
a = 4; b = 8; c = -45;
Δ = b2-4ac
Δ = 82-4·4·(-45)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-28}{2*4}=\frac{-36}{8} =-4+1/2 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+28}{2*4}=\frac{20}{8} =2+1/2 $
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