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(1/5)x=7-(4/5)
We move all terms to the left:
(1/5)x-(7-(4/5))=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/5)x-(7-(+4/5))=0
We multiply parentheses
x^2-(7-(+4/5))=0
We multiply all the terms by the denominator
x^2*5))-(7-(+4=0
Wy multiply elements
5x^3+4=0
We do not support expression: x^3
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