(3x+2+5x-4)2=36

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Solution for (3x+2+5x-4)2=36 equation: 



(3x+2+5x-4)2=36

We move all terms to the left:

(3x+2+5x-4)2-(36)=0

We add all the numbers together, and all the variables

(8x-2)2-36=0

We multiply parentheses

16x-4-36=0

We add all the numbers together, and all the variables

16x-40=0

We move all terms containing x to the left, all other terms to the right

16x=40

x=40/16

x=2+1/2

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