(1/5)x+(1/3)=-5

Solution for (1/5)x+(1/3)=-5 equation:

(1/5)x+(1/3)=-5

We move all terms to the left:

(1/5)x+(1/3)-(-5)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/5)x+(+1/3)-(-5)=0

We add all the numbers together, and all the variables

(+1/5)x+5+(+1/3)=0

We multiply parentheses

x^2+5+(+1/3)=0

We get rid of parentheses

x^2+5+1/3=0

We multiply all the terms by the denominator


x^2*3+1+5*3=0

We add all the numbers together, and all the variables

x^2*3+16=0

Wy multiply elements

3x^2+16=0

a = 3; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·3·16
Δ = -192
Delta is less than zero, so there is no solution for the equation