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(3x-4)(5x+9)=124
We move all terms to the left:
(3x-4)(5x+9)-(124)=0
We multiply parentheses ..
(+15x^2+27x-20x-36)-124=0
We get rid of parentheses
15x^2+27x-20x-36-124=0
We add all the numbers together, and all the variables
15x^2+7x-160=0
a = 15; b = 7; c = -160;
Δ = b2-4ac
Δ = 72-4·15·(-160)
Δ = 9649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{9649}}{2*15}=\frac{-7-\sqrt{9649}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{9649}}{2*15}=\frac{-7+\sqrt{9649}}{30} $
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