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(1/4x+12)=1/2x
We move all terms to the left:
(1/4x+12)-(1/2x)=0
Domain of the equation: 4x+12)!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(1/4x+12)-(+1/2x)=0
We get rid of parentheses
1/4x-1/2x+12=0
We calculate fractions
2x/8x^2+(-4x)/8x^2+12=0
We multiply all the terms by the denominator
2x+(-4x)+12*8x^2=0
Wy multiply elements
96x^2+2x+(-4x)=0
We get rid of parentheses
96x^2+2x-4x=0
We add all the numbers together, and all the variables
96x^2-2x=0
a = 96; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·96·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*96}=\frac{0}{192} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*96}=\frac{4}{192} =1/48 $
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