11-(n-4)=3(n+2)

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Solution for 11-(n-4)=3(n+2) equation: 



11-(n-4)=3(n+2)

We move all terms to the left:

11-(n-4)-(3(n+2))=0

We get rid of parentheses

-n-(3(n+2))+4+11=0



We calculate terms in parentheses: -(3(n+2)), so:

3(n+2)

We multiply parentheses

3n+6

Back to the equation:

-(3n+6)



We add all the numbers together, and all the variables

-1n-(3n+6)+15=0

We get rid of parentheses

-1n-3n-6+15=0

We add all the numbers together, and all the variables

-4n+9=0

We move all terms containing n to the left, all other terms to the right

-4n=-9

n=-9/-4

n=2+1/4

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