(1/4)(x-2)+4=12

Solution for (1/4)(x-2)+4=12 equation:

(1/4)(x-2)+4=12

We move all terms to the left:

(1/4)(x-2)+4-(12)=0


Domain of the equation: 4)(x-2)!=0

x∈R


We add all the numbers together, and all the variables

(+1/4)(x-2)+4-12=0

We add all the numbers together, and all the variables

(+1/4)(x-2)-8=0

We multiply parentheses ..

(+x^2+1/4*-2)-8=0

We multiply all the terms by the denominator


(+x^2+1-8*4*-2)=0

We get rid of parentheses

x^2+1-2-8*4*=0

We add all the numbers together, and all the variables

x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$