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6(2x+1)=2(x-4)
We move all terms to the left:
6(2x+1)-(2(x-4))=0
We multiply parentheses
12x-(2(x-4))+6=0
We calculate terms in parentheses: -(2(x-4)), so:We get rid of parentheses
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
12x-2x+8+6=0
We add all the numbers together, and all the variables
10x+14=0
We move all terms containing x to the left, all other terms to the right
10x=-14
x=-14/10
x=-1+2/5
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