(1/3)z+(2/3)z=-2

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Solution for (1/3)z+(2/3)z=-2 equation:



(1/3)z+(2/3)z=-2
We move all terms to the left:
(1/3)z+(2/3)z-(-2)=0
Domain of the equation: 3)z!=0
z!=0/1
z!=0
z∈R
We add all the numbers together, and all the variables
(+1/3)z+(+2/3)z-(-2)=0
We add all the numbers together, and all the variables
(+1/3)z+(+2/3)z+2=0
We multiply parentheses
z^2+2z^2+2=0
We add all the numbers together, and all the variables
3z^2+2=0
a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation

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