If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(1+2x)=66
We move all terms to the left:
x(1+2x)-(66)=0
We add all the numbers together, and all the variables
x(2x+1)-66=0
We multiply parentheses
2x^2+x-66=0
a = 2; b = 1; c = -66;
Δ = b2-4ac
Δ = 12-4·2·(-66)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-23}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+23}{2*2}=\frac{22}{4} =5+1/2 $
| 9/5=3/2x | | -9y-7=7y+9 | | 3z=9;z= | | -2/5=1/5b-2/5b+3/5b | | 2(x+2)/7=5x+10 | | .5x+4=3x-2x | | 1/2x+4=3×-2× | | 81=h-17 | | 3x+13=-2x-11 | | (2x-3)/(3x-5)=-3/4 | | 3x+13=-2x+11 | | x/26=0.55 | | x/26=1 | | x/26=100 | | J.8.9+j=12.8 | | x+4(x-2)=3(x-9) | | 2m/7+6=10(m=14) | | -12(x-19)=3(x+16) | | 2m/7+6=10(m=14 | | 3x=42x−1 | | 3^x=4^2x−1 | | 3x-8/4=10 | | 4x+20=7x-20 | | 2(4x+3)=7x+10 | | 4x+20=24x-12 | | 5x+380=x | | 7x+2.7=-6x-7.9 | | 4(x-4)/2=6 | | 1/8X+x+3/4=0 | | .6x=220 | | 5)5x/7=8 | | 10x^2+10x-300=0 |