(1/3)x=248

Solution for (1/3)x=248 equation:

(1/3)x=248

We move all terms to the left:

(1/3)x-(248)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)x-248=0

We multiply parentheses

x^2-248=0

a = 1; b = 0; c = -248;
Δ = b2-4ac
Δ = 02-4·1·(-248)
Δ = 992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{992}=\sqrt{16*62}=\sqrt{16}*\sqrt{62}=4\sqrt{62}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{62}}{2*1}=\frac{0-4\sqrt{62}}{2}
=-\frac{4\sqrt{62}}{2}
=-2\sqrt{62}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{62}}{2*1}=\frac{0+4\sqrt{62}}{2}
=\frac{4\sqrt{62}}{2}
=2\sqrt{62}
$