(1/3)w+3=(2/3)w-5

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Solution for (1/3)w+3=(2/3)w-5 equation: 



(1/3)w+3=(2/3)w-5

We move all terms to the left:

(1/3)w+3-((2/3)w-5)=0



Domain of the equation: 3)w!=0

w!=0/1

w!=0

w∈R





Domain of the equation: 3)w-5)!=0

w!=0/1

w!=0

w∈R



We add all the numbers together, and all the variables

(+1/3)w-((+2/3)w-5)+3=0

We multiply parentheses

w^2-((+2/3)w-5)+3=0

We multiply all the terms by the denominator


w^2*3)w-5)-((+3*3)w-5)+2=0

We add all the numbers together, and all the variables

w^2*3)w-5)-(9w-5)+2=0

Wy multiply elements

3w^3=0

We do not support ewpression: w^3

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