-(x-3)+4x=2(x-1)+6

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Solution for -(x-3)+4x=2(x-1)+6 equation: 



-(x-3)+4x=2(x-1)+6

We move all terms to the left:

-(x-3)+4x-(2(x-1)+6)=0

We add all the numbers together, and all the variables

4x-(x-3)-(2(x-1)+6)=0

We get rid of parentheses

4x-x-(2(x-1)+6)+3=0



We calculate terms in parentheses: -(2(x-1)+6), so:

2(x-1)+6

We multiply parentheses

2x-2+6

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

3x-(2x+4)+3=0

We get rid of parentheses

3x-2x-4+3=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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