(1/3)(d-5)=1

Solution for (1/3)(d-5)=1 equation:

(1/3)(d-5)=1

We move all terms to the left:

(1/3)(d-5)-(1)=0


Domain of the equation: 3)(d-5)!=0

d∈R


We add all the numbers together, and all the variables

(+1/3)(d-5)-1=0

We multiply parentheses ..

(+d^2+1/3*-5)-1=0

We multiply all the terms by the denominator


(+d^2+1-1*3*-5)=0

We get rid of parentheses

d^2+1-5-1*3*=0

We add all the numbers together, and all the variables

d^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{2}=0$