8+3(7w-5)=-3(2w-1)+9w

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Solution for 8+3(7w-5)=-3(2w-1)+9w equation: 



8+3(7w-5)=-3(2w-1)+9w

We move all terms to the left:

8+3(7w-5)-(-3(2w-1)+9w)=0

We multiply parentheses

21w-(-3(2w-1)+9w)-15+8=0



We calculate terms in parentheses: -(-3(2w-1)+9w), so:

-3(2w-1)+9w

We add all the numbers together, and all the variables

9w-3(2w-1)

We multiply parentheses

9w-6w+3

We add all the numbers together, and all the variables

3w+3

Back to the equation:

-(3w+3)



We add all the numbers together, and all the variables

21w-(3w+3)-7=0

We get rid of parentheses

21w-3w-3-7=0

We add all the numbers together, and all the variables

18w-10=0

We move all terms containing w to the left, all other terms to the right

18w=10

w=10/18

w=5/9

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