(1/3)(18+12q)=6(2q-7)

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Solution for (1/3)(18+12q)=6(2q-7) equation: 



(1/3)(18+12q)=6(2q-7)

We move all terms to the left:

(1/3)(18+12q)-(6(2q-7))=0



Domain of the equation: 3)(18+12q)!=0

q∈R



We add all the numbers together, and all the variables

(+1/3)(12q+18)-(6(2q-7))=0

We multiply parentheses ..

(+12q^2+1/3*18)-(6(2q-7))=0

We multiply all the terms by the denominator


(+12q^2+1-((6(2q-7)))*3*18)=0



We calculate terms in parentheses: +(+12q^2+1-((6(2q-7)))*3*18), so:

+12q^2+1-((6(2q-7)))*3*18

determiningTheFunctionDomain
12q^2-((6(2q-7)))*3*18+1

Back to the equation:

+(12q^2-((6(2q-7)))*3*18+1)





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





We calculate terms in parentheses: +(12q^2-((6(2q-7)))*3*18+1), so:

12q^2-((6(2q-7)))*3*18+1





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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