(1/3)(15y-21)=(2/5)(10y-35)

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Solution for (1/3)(15y-21)=(2/5)(10y-35) equation: 



(1/3)(15y-21)=(2/5)(10y-35)

We move all terms to the left:

(1/3)(15y-21)-((2/5)(10y-35))=0



Domain of the equation: 3)(15y-21)!=0

y∈R





Domain of the equation: 5)(10y-35))!=0

y∈R



We add all the numbers together, and all the variables

(+1/3)(15y-21)-((+2/5)(10y-35))=0

We multiply parentheses ..

(+15y^2+1/3*-21)-((+2/5)(10y-35))=0

We calculate fractions


((+15y^2+1*5)(10y-35)))/(-21)*5)(10y-35))+3*)+()/(-21)*5)(10y-35))+3*)=0

We calculate fractions


(((+15y^2+1*5)(10y-35)))*(-21)*5)(10y-35))+3*))/((*(-21)*5)10y)+(-21)*5)(10y-35))+3*)+()*()/((*(-21)*5)10y)=0

We can not solve this equation

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