14+(5/7)-20=(4/7)x-4

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Solution for 14+(5/7)-20=(4/7)x-4 equation: 



14+(5/7)-20=(4/7)x-4

We move all terms to the left:

14+(5/7)-20-((4/7)x-4)=0



Domain of the equation: 7)x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+4/7)x-4)+14-20+(+5/7)=0

We add all the numbers together, and all the variables

-((+4/7)x-4)-6+(+5/7)=0

We get rid of parentheses

-((+4/7)x-4)-6+5/7=0

We calculate fractions


-6!=0

There is no solution for this equation

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