(1/3)(-12x)=-24

Solution for (1/3)(-12x)=-24 equation:

(1/3)(-12x)=-24

We move all terms to the left:

(1/3)(-12x)-(-24)=0


Domain of the equation: 3)(-12x)!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)(-12x)-(-24)=0

We add all the numbers together, and all the variables

(+1/3)(-12x)+24=0

We multiply parentheses ..

(-12x^2)+24=0

We get rid of parentheses

-12x^2+24=0

a = -12; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-12)·24
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{2}}{2*-12}=\frac{0-24\sqrt{2}}{-24}
=-\frac{24\sqrt{2}}{-24}
=-\frac{\sqrt{2}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{2}}{2*-12}=\frac{0+24\sqrt{2}}{-24}
=\frac{24\sqrt{2}}{-24}
=\frac{\sqrt{2}}{-1}
$