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(1/2x+39)+x=180
We move all terms to the left:
(1/2x+39)+x-(180)=0
Domain of the equation: 2x+39)!=0We add all the numbers together, and all the variables
x∈R
x+(1/2x+39)-180=0
We get rid of parentheses
x+1/2x+39-180=0
We multiply all the terms by the denominator
x*2x+39*2x-180*2x+1=0
Wy multiply elements
2x^2+78x-360x+1=0
We add all the numbers together, and all the variables
2x^2-282x+1=0
a = 2; b = -282; c = +1;
Δ = b2-4ac
Δ = -2822-4·2·1
Δ = 79516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{79516}=\sqrt{4*19879}=\sqrt{4}*\sqrt{19879}=2\sqrt{19879}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-282)-2\sqrt{19879}}{2*2}=\frac{282-2\sqrt{19879}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-282)+2\sqrt{19879}}{2*2}=\frac{282+2\sqrt{19879}}{4} $
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