(1/2n)+(1/2n)=n

Solution for (1/2n)+(1/2n)=n equation:

(1/2n)+(1/2n)=n

We move all terms to the left:

(1/2n)+(1/2n)-(n)=0


Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

(+1/2n)+(+1/2n)-n=0

We add all the numbers together, and all the variables

-1n+(+1/2n)+(+1/2n)=0

We get rid of parentheses

-1n+1/2n+1/2n=0

We multiply all the terms by the denominator


-1n*2n+1+1=0

We add all the numbers together, and all the variables

-1n*2n+2=0

Wy multiply elements

-2n^2+2=0

a = -2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-2)·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-2}=\frac{-4}{-4}
=1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-2}=\frac{4}{-4}
=-1
$