(1/2)z+6=(3/2)(z+6)

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Solution for (1/2)z+6=(3/2)(z+6) equation: 



(1/2)z+6=(3/2)(z+6)

We move all terms to the left:

(1/2)z+6-((3/2)(z+6))=0



Domain of the equation: 2)z!=0

z!=0/1

z!=0

z∈R





Domain of the equation: 2)(z+6))!=0

z∈R



We add all the numbers together, and all the variables

(+1/2)z-((+3/2)(z+6))+6=0

We multiply parentheses

z^2-((+3/2)(z+6))+6=0

We multiply parentheses ..

z^2-((+3z^2+3/2*6))+6=0

We multiply all the terms by the denominator


3z^2+z^2*2*6))-((+3+6*2*6))=0

We add all the numbers together, and all the variables

3z^2+z^2*2*6))-(75)=0

We add all the numbers together, and all the variables

3z^2+z^2*2*6))-75=0

Wy multiply elements

3z^2+12z^3*6=0

We do not support ezpression: z^3

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