2x+4+6x=3(x-2)

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Solution for 2x+4+6x=3(x-2) equation: 



2x+4+6x=3(x-2)

We move all terms to the left:

2x+4+6x-(3(x-2))=0

We add all the numbers together, and all the variables

8x-(3(x-2))+4=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

8x-3x+6+4=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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