(1/2)y-(1/8)=(7/8)

Solution for (1/2)y-(1/8)=(7/8) equation:

(1/2)y-(1/8)=(7/8)

We move all terms to the left:

(1/2)y-(1/8)-((7/8))=0


Domain of the equation: 2)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+1/2)y-(+1/8)-((+7/8))=0

We multiply parentheses

y^2-(+1/8)-((+7/8))=0

We get rid of parentheses

y^2-1/8-((+7/8))=0

We calculate fractions


y^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{2}=0$