-19/8x-7/4x=-99/20

Solution for -19/8x-7/4x=-99/20 equation:

-19/8x-7/4x=-99/20

We move all terms to the left:

-19/8x-7/4x-(-99/20)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

-19/8x-7/4x+99/20=0

We calculate fractions


12672x^2/1280x^2+(-3040x)/1280x^2+(-2240x)/1280x^2=0

We multiply all the terms by the denominator


12672x^2+(-3040x)+(-2240x)=0

We get rid of parentheses

12672x^2-3040x-2240x=0

We add all the numbers together, and all the variables

12672x^2-5280x=0

a = 12672; b = -5280; c = 0;
Δ = b2-4ac
Δ = -52802-4·12672·0
Δ = 27878400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{27878400}=5280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5280)-5280}{2*12672}=\frac{0}{25344}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5280)+5280}{2*12672}=\frac{10560}{25344}
=5/12
$