(1/2)x+4+10=x-2

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Solution for (1/2)x+4+10=x-2 equation:



(1/2)x+4+10=x-2
We move all terms to the left:
(1/2)x+4+10-(x-2)=0
Domain of the equation: 2)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)x-(x-2)+4+10=0
We add all the numbers together, and all the variables
(+1/2)x-(x-2)+14=0
We multiply parentheses
x^2-(x-2)+14=0
We get rid of parentheses
x^2-x+2+14=0
We add all the numbers together, and all the variables
x^2-1x+16=0
a = 1; b = -1; c = +16;
Δ = b2-4ac
Δ = -12-4·1·16
Δ = -63
Delta is less than zero, so there is no solution for the equation

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