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(1/2)x+3=2(x-2.5)
We move all terms to the left:
(1/2)x+3-(2(x-2.5))=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/2)x-(2(x-2.5))+3=0
We multiply parentheses
x^2-(2(x-2.5))+3=0
We calculate terms in parentheses: -(2(x-2.5)), so:We get rid of parentheses
2(x-2.5)
We multiply parentheses
2x-5
Back to the equation:
-(2x-5)
x^2-2x+5+3=0
We add all the numbers together, and all the variables
x^2-2x+8=0
a = 1; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation
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