4(m+5)=6(m-2)

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Solution for 4(m+5)=6(m-2) equation: 



4(m+5)=6(m-2)

We move all terms to the left:

4(m+5)-(6(m-2))=0

We multiply parentheses

4m-(6(m-2))+20=0



We calculate terms in parentheses: -(6(m-2)), so:

6(m-2)

We multiply parentheses

6m-12

Back to the equation:

-(6m-12)



We get rid of parentheses

4m-6m+12+20=0

We add all the numbers together, and all the variables

-2m+32=0

We move all terms containing m to the left, all other terms to the right

-2m=-32

m=-32/-2

m=+16

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