(1/2)x(x+2)=((1/2)x+2)(x+3)

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Solution for (1/2)x(x+2)=((1/2)x+2)(x+3) equation: 



(1/2)x(x+2)=((1/2)x+2)(x+3)

We move all terms to the left:

(1/2)x(x+2)-(((1/2)x+2)(x+3))=0



Domain of the equation: 2)x(x+2)!=0

x∈R





Domain of the equation: 2)x+2)(x+3))!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)x(x+2)-(((+1/2)x+2)(x+3))=0

We calculate fractions


(2x+2)x/2x(x+2)*2)x+2)(x+3)))+(-((2x(x+2))/2x(x+2)*2)x+2)(x+3)))=0

We calculate fractions


((2x+2)x*2x(x+2)*2)x+2)(x+3))))/(2x(x+2)*2)x+2)(x+3)))+(-((2x(x*2x(x+2)*2)x+2)(x+3))))+2)*2x(x+2)*2)x+2)(x+3)))+(-((2xx/(2x(x+2)*2)x+2)(x+3)))+(-((2x(x*2x(x+2)*2)x+2)(x+3))))=0

We can not solve this equation

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