(1/2)x(-10x+4)=-4(-3+2x)+8

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Solution for (1/2)x(-10x+4)=-4(-3+2x)+8 equation: 



(1/2)x(-10x+4)=-4(-3+2x)+8

We move all terms to the left:

(1/2)x(-10x+4)-(-4(-3+2x)+8)=0



Domain of the equation: 2)x(-10x+4)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)x(-10x+4)-(-4(2x-3)+8)=0

We multiply all the terms by the denominator


(+1-((-4(2x-3)+8))*2)x(-10x+4)=0



We calculate terms in parentheses: +(+1-((-4(2x-3)+8))*2)x(-10x+4), so:

+1-((-4(2x-3)+8))*2)x(-10x+4

determiningTheFunctionDomain
-((-4(2x-3)+8))*2)x(-10x+1+4

We add all the numbers together, and all the variables

-10x-((-4(2x-3)+8))*2)x(+5

Back to the equation:

+(-10x-((-4(2x-3)+8))*2)x(+5)



We add all the numbers together, and all the variables

(-10x-((-4(2x-3)+8))*2)x5=0

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