(1/2)r+6=3+2r

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Solution for (1/2)r+6=3+2r equation: 



(1/2)r+6=3+2r

We move all terms to the left:

(1/2)r+6-(3+2r)=0



Domain of the equation: 2)r!=0

r!=0/1

r!=0

r∈R



We add all the numbers together, and all the variables

(+1/2)r-(2r+3)+6=0

We multiply parentheses

r^2-(2r+3)+6=0

We get rid of parentheses

r^2-2r-3+6=0

We add all the numbers together, and all the variables

r^2-2r+3=0

a = 1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation

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