(4/x+2)=7/2x-7

Solution for (4/x+2)=7/2x-7 equation:

(4/x+2)=7/2x-7

We move all terms to the left:

(4/x+2)-(7/2x-7)=0


Domain of the equation: x+2)!=0

x∈R



Domain of the equation: 2x-7)!=0

x∈R


We get rid of parentheses

4/x-7/2x+2+7=0

We calculate fractions


8x/2x^2+(-7x)/2x^2+2+7=0

We add all the numbers together, and all the variables

8x/2x^2+(-7x)/2x^2+9=0

We multiply all the terms by the denominator


8x+(-7x)+9*2x^2=0

Wy multiply elements

18x^2+8x+(-7x)=0

We get rid of parentheses

18x^2+8x-7x=0

We add all the numbers together, and all the variables

18x^2+x=0

a = 18; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·18·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*18}=\frac{-2}{36}
=-1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*18}=\frac{0}{36}
=0
$