(1/2)b+(9/4)=(7/4)

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Solution for (1/2)b+(9/4)=(7/4) equation: 



(1/2)b+(9/4)=(7/4)

We move all terms to the left:

(1/2)b+(9/4)-((7/4))=0



Domain of the equation: 2)b!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+1/2)b+(+9/4)-((+7/4))=0

We multiply parentheses

b^2+(+9/4)-((+7/4))=0

We get rid of parentheses

b^2+9/4-((+7/4))=0

We calculate fractions


b^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{2}=0$

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