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(1/2)(x-4)=3
We move all terms to the left:
(1/2)(x-4)-(3)=0
Domain of the equation: 2)(x-4)!=0We add all the numbers together, and all the variables
x∈R
(+1/2)(x-4)-3=0
We multiply parentheses ..
(+x^2+1/2*-4)-3=0
We multiply all the terms by the denominator
(+x^2+1-3*2*-4)=0
We get rid of parentheses
x^2+1-4-3*2*=0
We add all the numbers together, and all the variables
x^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{2}=0$
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