A(n)=4+(n+-1)(-3)

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Solution for A(n)=4+(n+-1)(-3) equation: 



(A)=4+(A+-1)(-3)

We move all terms to the left:

(A)-(4+(A+-1)(-3))=0

We add all the numbers together, and all the variables

A-(4+(A-1)(-3))=0

We multiply parentheses ..

A-(4+(-3A+3))=0



We calculate terms in parentheses: -(4+(-3A+3)), so:

4+(-3A+3)

determiningTheFunctionDomain
(-3A+3)+4

We get rid of parentheses

-3A+3+4

We add all the numbers together, and all the variables

-3A+7

Back to the equation:

-(-3A+7)



We get rid of parentheses

A+3A-7=0

We add all the numbers together, and all the variables

4A-7=0

We move all terms containing A to the left, all other terms to the right

4A=7

A=7/4

A=1+3/4

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