(1/2)(x-3)=9

Solution for (1/2)(x-3)=9 equation:

(1/2)(x-3)=9

We move all terms to the left:

(1/2)(x-3)-(9)=0


Domain of the equation: 2)(x-3)!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)(x-3)-9=0

We multiply parentheses ..

(+x^2+1/2*-3)-9=0

We multiply all the terms by the denominator


(+x^2+1-9*2*-3)=0

We get rid of parentheses

x^2+1-3-9*2*=0

We add all the numbers together, and all the variables

x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$